NEW FUNCTION

Function Expression :

\[f(x)=1-ln(e^{-x}+1 ) \]

Domain

\[\left]-\infty, \infty\right[ \]

Limits

\[\lim_{x \rightarrow-\infty}f(x) = -\infty \]
\[\lim_{x \rightarrow+\infty}f(x) = 1 \]
\[ \]

Derivate

\[f^{\,\prime}(x)=\frac{e^{- x}}{1 + e^{- x}} \]
\[f^{\,\prime}(x)=\frac{1}{e^{x} + 1} \]
\[ \]

Integral

\[F(x) = - x \log{\left(1 + e^{- x} \right)} - \int \frac{x}{e^{x} + 1}\, dx - \int \left(- \frac{e^{x}}{e^{x} + 1}\right)\, dx - \int \left(- \frac{1}{e^{x} + 1}\right)\, dx \]

Sign Table


Variation Table


Plot


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