NEW FUNCTION

Function Expression :

\[f(x)=sin(\frac{x+1}{2x+1} ) \]

Domain

\[\left]-\infty, - \frac{1}{2}\right[ \cup \left]- \frac{1}{2}, \infty\right[ \]

Limits

\[\lim_{x \rightarrow-\infty}f(x) = \sin{\left(\frac{1}{2} \right)} \]
\[\lim_{x \overset{<}{\rightarrow- \frac{1}{2}} }f(x) = \left\langle -1, 1\right\rangle \]
\[\lim_{x \overset{>}{\rightarrow- \frac{1}{2}} }f(x) = \left\langle -1, 1\right\rangle \]
\[\lim_{x \rightarrow+\infty}f(x) = \sin{\left(\frac{1}{2} \right)} \]
\[ \]

Derivate

\[f^{\,\prime}(x)=\left(- \frac{2 \left(x + 1\right)}{\left(2 x + 1\right)^{2}} + \frac{1}{2 x + 1}\right) \cos{\left(\frac{x + 1}{2 x + 1} \right)} \]
\[f^{\,\prime}(x)=- \frac{\cos{\left(\frac{x + 1}{2 x + 1} \right)}}{\left(2 x + 1\right)^{2}} \]
\[ \]

Integral

\[F(x) = \int \sin{\left(\frac{x + 1}{2 x + 1} \right)}\, dx \]

Sign Table


Variation Table


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